FindRoot[10^x==10*x, {x,0.135}, WorkingPrecision->50]
10^0.13712885742386235368613621063 = 10*0.13712885742386235368613621063 = 1.3712885742386235368613621063
the other root is 10^1 = 10*1 .
the nontrivial root only exists when the base is greater than e, so there is no binary version.
4^(1/2) = 4*(1/2) = 2. is this the only rational solution?
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