Uses the return value of the program $1 to determine success.
#!/bin/bash set -x if [ -z "$1" ] then echo "need program" exit 1 fi lo=1 hi=1000000000 while expr \( $lo + 1 \) \< $hi do mid=`expr \( $lo + $hi \) / 2 ` if time "$1" $mid then lo=$mid else hi=$mid fi sleep 1 done
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